Q) If 𝑦=𝑃cos 𝑒π‘₯+𝑄sin 𝑒π‘₯, show that (𝑑^2 𝑦)/(𝑑π‘₯^2 )+𝑒^2 𝑦=0. #cbse2026 #maths #different
1:45
YouTubeShivang Maths Academy
Q) If 𝑦=𝑃cos 𝑒π‘₯+𝑄sin 𝑒π‘₯, show that (𝑑^2 𝑦)/(𝑑π‘₯^2 )+𝑒^2 𝑦=0. #cbse2026 #maths #different
Q) If 𝑦=𝑃cos 𝑒π‘₯+𝑄sin 𝑒π‘₯, show that (𝑑^2 𝑦)/(𝑑π‘₯^2 )+𝑒^2 𝑦=0. CBSE Class 12 Maths PYQ 2026 | Continuity of Piecewise Function at x = 3 | Board Exam Question | Functions Chapter class 12th maths chapter number 5 Medium volume : class 12 maths chapter 5 exercise 5.1 High volume β€’ Content gap for Shorts ...
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Q) Find the value of a and b so that function f defined as:𝐟(𝐱)={((π±βˆ’πŸ)/|π±βˆ’πŸ| +𝐚, 𝐒𝐟 𝐱=𝟐
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Q) Find the value of a and b so that function f defined as:𝐟(𝐱)={((π±βˆ’πŸ)/|π±βˆ’πŸ| +𝐚, 𝐒𝐟 𝐱=𝟐
Shivang Maths Academy
Q) The value of k for which f(x)={(sin7x/5x,x≠0 k,x=0) is continuous at x=0 is
1:19
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Q) The value of k for which f(x)={(sin7x/5x,x≠0 k,x=0) is continuous at x=0 is
Shivang Maths Academy
Continuity and Discontinuity
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Q) If 2cos^(βˆ’1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Q) If 2cos^(βˆ’1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Q) Simplify: 𝐜𝐨𝐬^(βˆ’πŸ) 𝐱+𝐜𝐨𝐬^(βˆ’πŸ) [𝐱/𝟐+√(πŸ‘βˆ’πŸ‘π±^𝟐 )/𝟐]; 𝟏/πŸβ‰€π±β‰€πŸ #cbsemaths #maths
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Q) Simplify: 𝐜𝐨𝐬^(βˆ’πŸ) 𝐱+𝐜𝐨𝐬^(βˆ’πŸ) [𝐱/𝟐+√(πŸ‘βˆ’πŸ‘π±^𝟐 )/𝟐]; 𝟏/πŸβ‰€π±β‰€πŸ #cbsemaths #maths
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Q) If 2cos^(βˆ’1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Q) If 2cos^(βˆ’1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Q) Simplify: 𝐜𝐨𝐬^(βˆ’πŸ) 𝐱+𝐜𝐨𝐬^(βˆ’πŸ) [𝐱/𝟐+√(πŸ‘βˆ’πŸ‘π±^𝟐 )/𝟐]; 𝟏/πŸβ‰€π±β‰€πŸ #cbsemaths #maths
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Q) Simplify: 𝐜𝐨𝐬^(βˆ’πŸ) 𝐱+𝐜𝐨𝐬^(βˆ’πŸ) [𝐱/𝟐+√(πŸ‘βˆ’πŸ‘π±^𝟐 )/𝟐]; 𝟏/πŸβ‰€π±β‰€πŸ #cbsemaths #maths
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YouTubeShivang Maths Academy
Q) Find the value of a and b so that function f defined as:𝐟(𝐱)={((π±βˆ’πŸ)/|π±βˆ’πŸ| +𝐚, 𝐒𝐟 𝐱=𝟐
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Q) Find the value of a and b so that function f defined as:𝐟(𝐱)={((π±βˆ’πŸ)/|π±βˆ’πŸ| +𝐚, 𝐒𝐟 𝐱=𝟐
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Q) The value of k for which f(x)={(sin7x/5x,x≠0 k,x=0) is continuous at x=0 is
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Q) The value of k for which f(x)={(sin7x/5x,x≠0 k,x=0) is continuous at x=0 is
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Q) Check whether function f(x) defined as f(π‘₯)={((|π‘₯βˆ’3|)/(2(π‘₯βˆ’3)), π‘₯=3 (π‘₯βˆ’6)/6,π‘₯β‰₯3) Is
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Q) Check whether function f(x) defined as f(π‘₯)={((|π‘₯βˆ’3|)/(2(π‘₯βˆ’3)), π‘₯=3 (π‘₯βˆ’6)/6,π‘₯β‰₯3) Is
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Q) The value of π‘˜ for which the function 𝑓(π‘₯)={(π‘₯^2 sin 1/π‘₯, π‘₯β‰ 0 π‘˜(π‘₯+1), π‘₯=0) is a continuo
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Q) The value of π‘˜ for which the function 𝑓(π‘₯)={(π‘₯^2 sin 1/π‘₯, π‘₯β‰ 0 π‘˜(π‘₯+1), π‘₯=0) is a continuo
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1:07
Q) If 𝑓(π‘₯)={(sinπ‘₯/π‘₯+cosπ‘₯, π‘₯β‰ 0 π‘˜, π‘₯=0) is continuous at π‘₯=0, then the value of π‘˜ is :
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1:09
Q) If 𝑓(π‘₯)={(3π‘₯βˆ’2, 0≀π‘₯≀1 2π‘₯^2+π‘Žπ‘₯, 1≀π‘₯≀2) is continuous for π‘₯∈(0,2), then a is equal to
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1:50
Q) If 𝑠𝑖𝑛 π‘π‘œπ‘‘^(βˆ’1) (π‘₯+1)]=π‘π‘œπ‘ (tan^(βˆ’1) π‘₯), π‘‘β„Žπ‘’π‘› 𝑓𝑖𝑛𝑑 π‘₯.#class12maths #shivang
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1:01
If a function defined by 𝑓(π‘₯)={(π‘˜π‘₯+1, π‘₯β‰€πœ‹ cosπ‘₯ ,π‘₯=πœ‹) is continuous at π‘₯=πœ‹, then the val
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0:56
Q) If sin^(βˆ’1) π‘₯=𝑦,then 𝑑𝑦/𝑑π‘₯ is #maths #continuityanddifferentiabilityclass12 #class12 #cbse
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2:22
Find k so that 𝑓(π‘₯)={((π‘₯^2βˆ’2π‘₯βˆ’3)/(π‘₯+1), π‘₯β‰ βˆ’1 π‘˜, π‘₯=βˆ’1) is continuous at x=βˆ’1.#cbse2027 #maths
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1:53
Q) If 𝑓(π‘₯)={((1βˆ’sin^3 π‘₯)/(3cos^2 π‘₯), for π‘₯β‰ πœ‹/2 π‘˜, for π‘₯=πœ‹/2) is continuous at π‘₯=πœ‹/2, t
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1:44
Find the value of k for which the function 𝐟(𝐱)={((πŸβˆ’πœπ¨π¬π±)/(𝟐𝐱^𝟐 ), 𝐒𝐟 π±β‰ πŸŽ 𝐀, 𝐒𝐟
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Q) If sin^(βˆ’1) π‘₯ + pie =3𝑦, thenCBSE Class 12 Maths PYQ 2026 | Continuity of Piecewise Function
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1:50
Q) The function 𝑓 defined by 𝑓(π‘₯)={ (π‘₯,f π‘₯≀1 5, if π‘₯= 1 is not continuous at(A) x=0(B) π‘₯
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Q) If 𝑓(π‘₯)={ ((π‘₯^2βˆ’4π‘₯βˆ’5)/(π‘₯+1), π‘₯β‰ βˆ’1 π‘˜,&π‘₯=βˆ’1 is continuous at π‘₯=βˆ’1, then the value of π‘˜ i
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1:46
Q) Find the value of π‘˜, so that 𝑓(π‘₯)={(π‘˜cosπ‘₯/(πœ‹βˆ’2π‘₯), if π‘₯β‰ πœ‹/2@3, if π‘₯=πœ‹/2) is continu
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